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Now, assume that MyWebServer is registered in the DNS as www.MyDomain.com and is exposed to the Internet. You could then use the following URL: http://www.MyDomain.com/MyWebApp Finally, you can always use the computer s IP address, provided the computer is on the same network or visible on the Internet. Assuming the IP address is 123.5.123.4, here s the URL you would use: http://123.5.123.4/MyWebApp Because internal networks often use dynamic IP addresses and because DNS registration changes, using the computer name or domain name to access a website is almost always the best approach. If you study the URLs that the built-in web server in Visual Studio uses, you ll notice they re a little different than what you usually see when surfing the Internet. Namely, they include a port number. That means instead of requesting a page like this: http://localhost/MyWebApp/Default.aspx you might request a page like this: http://localhost:2040/MyWebApp/Default.aspx That s because the Visual Studio web server watches requests on a dynamically chosen port number. (In this example, the port number is 2040, but you ll see that it changes each time you run Visual Studio.) By using a dynamic port number, Visual Studio makes sure its built-in web server doesn t infringe on any other web server software you have on the computer. Real web servers are almost always configured to monitor port 80 (and port 443 for encrypted traffic). If you don t type in a port number for a URL, the browser assumes you re using port 80 for ordinary web access and port 443 for secure connections.

Some applications run on web farms, a group of server computers that share the responsibility of handling requests. Usually web farms are reserved for high-powered web applications that need to be able to handle heavy loads, because multiple computers can deal with more simultaneous surfers than a single web server. However, web farms are overkill for many small and midsized websites. The way a web farm works is deceptively simple. Essentially, instead of placing web application files on a single web server, you place a copy on several separate web servers. When a request is received for your website, it s directed to one of these web servers (based on which one has the lightest load). That web server then deals with the request. Obviously, if you decide to update your application, you need to make sure you update each web server in the web farm with the same version to prevent discrepancies. Some web hosting companies use web farms to host multiple websites. For example, your website might be running on more than one web server, but each of these web servers might also host multiple websites. This provides a flexible deployment model that lets different web applications share resources. However, web farms also introduce a few new challenges. If you re setting up a web farm of your own, you ll need to make sure each computer uses the same machine key, as described later in this chapter in the section The Machine Key.

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Figure 8-6. Sample event XML c. Using a Visual Studio command prompt, execute the following command-line statement. This statement tells the RFID client utility to publish the event in the XML document to a specific logical device within a specified process. rfidclientconsole -m localhost AddEventToProcessPipeline PublishToBizTalk rfidsample.xml MSMQDemoDevice d. After the event has been sent, you need to check several items: i. Check the event viewer for any errors. If an exception occurs during processing of the event, it will be

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public void commandAction(Command c, Displayable s) { if (c.getCommandType() == Command.EXIT) notifyDestroyed(); else { Form waitForm = new Form("Loading..."); mDisplay.setCurrent(waitForm); Thread t = new Thread(this); t.start(); } } public void run() { String selection = mMainScreen.getString( mMainScreen.getSelectedIndex()); boolean viaHttp = selection.equals("Via HTTP"); if (viaHttp) playViaHttp(); else playFromResource(); } private void playViaHttp() { try { String url = getAppProperty("AudioMIDlet-URL"); Player player = Manager.createPlayer(url); player.start(); } catch (Exception e) { showException(e); return; } mDisplay.setCurrent(mMainScreen); } private void playFromResource() { try { InputStream in = getClass().getResourceAsStream("/relax.wav"); Player player = Manager.createPlayer(in, "audio/x-wav"); player.start(); } catch (Exception e) { showException(e); return; } mDisplay.setCurrent(mMainScreen); }

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